An unknown ether, upon treatment with HI, produces a single alkyl iodide. This alkyl iodide, when reacted with sodium in dry ether, forms n-hexane. Identify the original ether.
Diethyl ether
Dipropyl ether
Dibutyl ether
Diisopropyl ether
Related Questions
reacts with=— under anhydrous conditions at room temperature to give:
and C
and
——
——
The products obtained when benzyl phenyl ether is heated with HI in the mole ratio 1:1 are
I. Phenol
II. Benzyl alcohol
III. Benzyl iodide
IV. Iodobenzene
1 and 3 only
3 and 4 only
1 and 4 only
2 and 4 only
On boiling with conc. hydrobromic acid, phenylethylether will yield:
Phenol and ethyl bromide
Bromobenzene and ethanol
Phenol and ethane
Bromobenzene and ethane
Arrange the following ethers in decreasing order of their reactivity towards cleavage with HI:
(i)
(ii)
(iii)
(iv)
i > ii > iii > iv
iv > iii > ii > i
iii > iv > ii > i
i > ii > iv > iii
An example of a compound with functional group —— is:
Acetic acid
Methyl alcohol
Diethyl ether
Acetone
Which of the following reagents is used in the Williamson ether synthesis?
Sodium alkoxide and alkyl halide
Alcohol and alkyl halide
Sodium alkoxide and alcohol
Alkyl halide and alkyl halide
Which of the following compounds is resistant to nucleophilic attack by hydroxyl ions?
Acetamide
Methyl acetate
Diethyl ether
Acetonitrile
The reaction of with gives:
CH3I and C2H5I
CH3OH and C2H5I
CH3I and C2H5OH
CH3OH and C2H5OH
Ether on reacting with form
Diethyl sulphide
Thioalcohol
Thioether
Thioaldehyde
In Williamson’s synthesis
An alkyl halide is treated with sodium alkoxide
An alkyl halide is treated with sodium
An alcohol is heated with conc.
None of the above