An unknown ether, upon treatment with HI, produces a single alkyl iodide. This alkyl iodide, when reacted with sodium in dry ether, forms n-hexane. Identify the original ether.
Diethyl ether
Dipropyl ether
Dibutyl ether
Diisopropyl ether
Related Questions
The reaction of with gives:
only
only
reacts with hot and excess HI, then formed product is
None of the above
The reaction of with gives:
CH3I and C2H5I
CH3OH and C2H5I
CH3I and C2H5OH
CH3OH and C2H5OH
Anisole is treated with excess HI. What is the major product formed?
Phenol and methyl iodide
Iodobenzene and methanol
Benzene and methanol
o-iodoanisole and water
Which of the following compounds when heated with CO at 150 and 500 atm pressure in presence of forms ethyl propionate?
Ether on reacting with form
Diethyl sulphide
Thioalcohol
Thioether
Thioaldehyde
The reaction of diethyl ether with one equivalent of HI at room temperature primarily yields:
Two molecules of ethyl iodide
Ethyl iodide and ethanol
Diethyl ether and HI remain unreacted
Ethene and ethanol
reacts with=β under anhydrous conditions at room temperature to give:
and C
and
ββ
ββ
-butyl methyl ether on heating with anhydrous HI in ether gives
tert-butyl iodide and methanol
tert-butyl alcohol and methyl iodide
isobutylene and methyl iodide
tert-butyl iodide and water
On boiling with conc. hydrobromic acid, phenylethylether will yield:
Phenol and ethyl bromide
Bromobenzene and ethanol
Phenol and ethane
Bromobenzene and ethane