An unknown ether, upon treatment with HI, produces a single alkyl iodide. This alkyl iodide, when reacted with sodium in dry ether, forms n-hexane. Identify the original ether.
Diethyl ether
Dipropyl ether
Dibutyl ether
Diisopropyl ether
Related Questions
Which of the following ethers form peroxide readily?
Which of the following is not isomeric with diethyl ether?
Methyl propyl ether
Butan-1-ol
2-methyl propan-2-ol
Butan-2-one
reacts with hot and excess HI, then formed product is
None of the above
reacts with hot and excess HI, then formed product is
None of the above
The products formed in the following reaction,
ββ are:
and
and
and
and
The cleavage of an aryl-alkyl ether with hydrogen halide will give:
A molecule each of an alkyl halide and water
A molecule each of an aryl halide and water
A molecule each of an alkyl halide, aryl halide and water
A molecule each of phenol and an alkyl halide
on reaction with will give:
One mole of an organic compound with the formula reacts completely with two moles of HI to form and . When is boiled with aqueous alkali it forms . answers the iodoform test. The compound is
Propan-2-ol
Methoxyethane
Propan-1-ol
Propane-1,2-diol
-butyl methyl ether on heating with anhydrous HI in ether gives
None of the above
A Wittig reaction with an aldehyde gives
Ketone compound
A long chain fatty acid
Olefin compound
Epoxide