An unknown ether, upon treatment with HI, produces a single alkyl iodide. This alkyl iodide, when reacted with sodium in dry ether, forms n-hexane. Identify the original ether.
Diethyl ether
Dipropyl ether
Dibutyl ether
Diisopropyl ether
Related Questions
Diethyl ether is decomposed on heating with:
Water
Ethyl chloride is converted into diethyl ether by
Perkins reaction
Grignard reagent
Wurtz reaction
Williamson’s synthesis
Diethyl ether is decomposed on heating with:
Water
In Williamson’s synthesis ethoxy ethane is prepared by
Passing ethanol over heated alumina
Heating sodium ethoxide with ethyl bromide
Treating ethyl alcohol with excess of at 430-440 K
Heating ethanol with dry
Which of the following reactions does not yield an ether?
Williamson ether synthesis
Alkoxymercuration-demercuration
Dehydration of alcohols
Reaction of phenols with alkyl halides
on reaction with will give:
One mole of an organic compound with the formula reacts completely with two moles of HI to form and . When is boiled with aqueous alkali it forms . answers the iodoform test. The compound is
Propan-2-ol
Methoxyethane
Propan-1-ol
Propane-1,2-diol
The cleavage of an aryl-alkyl ether with cold HI gives
Alkyl iodide and water
Aryl iodide and water
Alkyl iodide, aryl iodide and water
Phenol and alkyl iodine
On boiling with concentrated hydrobromic acid, phenyl ethyl ether yields
Phenol and ethane
Phenol and ethyl bromide
Bromobenzene and ethanol
Bromobenzene and ethane
Ethyl iodide on treatment with dry will yield:
Ethyl alcohol
Diethyl ether
Ethyl methyl ether
Ethylene