The Question is from neet-chemistry , and it was created by the author Mr. S M HUSSAIN

Question

Acidic nature of ${\rm{Zn}}{\left( {{\rm{OH}}} \right)_2}$ is shown from the formation of the following compound with the formula:

Mr. S M HUSSAIN · Accepted Answer

## CORE INFORMATION
✓ **Answer**: [A]
## CONCEPT FRAMEWORK
	**Primary Concept**: Amphoteric nature of metal hydroxides
	**Related Topics**: Acid-base reactions, Formation of complex ions
	**Prerequisites**: Knowledge of common metal hydroxides, understanding of acidic and basic behavior.
## SOLUTION PATHWAY
**Given Information**:
	Zinc hydroxide, ${m{Zn(OH)}_2}$, is reacting to show its acidic nature.
	We need to identify a product that indicates this acidic behavior.
**Method & Steps**:
	1. **Understanding Amphoteric Nature:** Zinc hydroxide is amphoteric, meaning it can act as both an acid and a base. To show its acidic nature, it must react with a strong base (like NaOH).
		Reasoning: When an amphoteric hydroxide reacts with a strong base, it forms a salt where the metal is part of the anion.
		Formula/Rule: General reaction: ${m{Metal(OH)}_2}$ + 2NaOH → ${m{Na}}_2{m{MetalO}}_2$ + 2${m{H}}_2{m{O}}$
	2. **Applying to Zinc Hydroxide:**  When ${m{Zn(OH)}_2}$ reacts with NaOH, the product will have a zincate anion, ${m{ZnO}}_2^{2-}$.
		Working: ${m{Zn(OH)}_2}$ + 2NaOH → ${m{Na}}_2{m{ZnO}}_2$ + 2${m{H}}_2{m{O}}$
		Key Point: The formation of ${m{Na}}_2{m{ZnO}}_2$ (sodium zincate) indicates the acidic nature of ${m{Zn(OH)}_2}$.
	3. **Final step**:
		Result: The correct compound is ${m{Na}}_2{m{ZnO}}_2$.
		Verification: The other options do not represent the product of a reaction between a metal hydroxide and a base, and option B is a salt of a weak acid.
 ## OPTION ANALYSIS
[A] ✓: ${m{N}}{{m{a}}_2}{m{Zn}}{{m{O}}_2}$ (Sodium zincate) is formed when ${m{Zn(OH)}_2}$ reacts with a strong base, indicating its acidic nature.
[B] :x: ${m{N}}{{m{a}}_2}{m{C}}{{m{O}}_3}$ is sodium carbonate, not related to the reaction of ${m{Zn(OH)}_2}$ with a strong base.
[C] :x: ${m{NaZn}}{{m{O}}_2}$ is not the correct formula of the sodium zincate.
[D] :x: This option is incorrect because option A is the correct answer.
 ## LEARNING AIDS
	**Common Mistakes**:
		1. [Error 1]: Confusing acidic and basic behavior of amphoteric hydroxides. [How to avoid]: Remember that amphoteric substances can react with both acids and bases.
		2. [Error 2]: Incorrectly writing chemical formulas of metal complex ions. [How to avoid]: Pay attention to the charge balance and the correct number of atoms in the formula.
	**Quick Tips**:
		1. [Helpful shortcut]: Think of amphoteric metal hydroxides as forming complex anions when reacting with strong bases.
		2. [Memory aid]: Remember that Zinc (Zn) is a common amphoteric metal and forms zincate anions when acting as an acid.

Mr. S M HUSSAIN · Answer

The correct Option is "${\rm{N}}{{\rm{a}}_2}{\rm{Zn}}{{\rm{O}}_2}$"

Mr. S M HUSSAIN · Answer

${\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3}$

Mr. S M HUSSAIN · Answer

${\rm{NaZn}}{{\rm{O}}_2}$

Mr. S M HUSSAIN · Answer

None of these

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