NEET Chemistry MCQs

A particle is projected with velocity $\vec{v} = (6\hat{i} + 8\hat{j})$ m/s. If $g = 10 m/s^2$, the radius of curvature of its trajectory at the highest point is:

A projectile is thrown with a speed u at an angle $heta$ to the horizontal. The radius of curvature of its trajectory when the velocity vector of the projectile makes an angle $\alpha$ with the horizontal is

A projectile is thrown with a speed u at an angle $heta$ to the horizontal. The radius of curvature of its trajectory when the velocity vector of the projectile makes an angle $\alpha$ with the horizontal is

A particle is projected from the ground at an angle of ${60^0}$ with horizontal with speed $u = 20{\rm{\;m}}{{\rm{s}}^{ - 1}}$. The radius of curvature of the path of the particle, when its velocity makes an angle of ${30^0}$ with horizontal is $\left( {{\rm{g\;}} = 10{\rm{\;m}}{{\rm{s}}^{ - 2}}} \right)$

A projectile is thrown with a speed u at an angle $heta$ to the horizontal. The radius of curvature of its trajectory when the velocity vector of the projectile makes an angle $\alpha$ with the horizontal is

A particle is projected from the ground at an angle of ${60^0}$ with horizontal with speed $u = 20{\rm{\;m}}{{\rm{s}}^{ - 1}}$. The radius of curvature of the path of the particle, when its velocity makes an angle of ${30^0}$ with horizontal is $\left( {{\rm{g\;}} = 10{\rm{\;m}}{{\rm{s}}^{ - 2}}} \right)$

A particle is projected from the ground at an angle of ${60^0}$ with horizontal with speed $u = 20{\rm{\;m}}{{\rm{s}}^{ - 1}}$. The radius of curvature of the path of the particle, when its velocity makes an angle of ${30^0}$ with horizontal is $\left( {{\rm{g\;}} = 10{\rm{\;m}}{{\rm{s}}^{ - 2}}} \right)$